# Ocean Tides

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Q . 1  Define Ocean Tides ?

A .  Ocean tides are the rise and fall of sea level due to the gravitational forces excerted by the Moon and the Sun and the rotation of the Earth .

Q . 2a  Describe the difference between flood and ebb currents .

A .  A flood current is during a high tide when water moves landward .

An ebb current is during low tide when water recedes seaward .

Q . 2b  When are flood and ebb current weak and strong ?

A .  The strongest flood and ebb currents usually occur before or near the time of high and low tides .

The weakest currents occur between the flood and ebb current called slack tides .

Q . 3 Write down Newton’s Laws of Universal Gravitation.

A .  Every point mass attracts every single other point mass by a force pointing along the line joining both points. This force is basically proportional to the product of the two masses and inversely proportional to the square of the distance between them.

,

where:

• F is the force between the masses,
• G is the gravitational constant  = 6.674×10−11 N m2 kg−2
• m1 is the first mass,
• m2 is the second mass, and
• r is the distance between the centers of the masses

Q . 4 Using Newton’s law of gravitational motion , which pulls the earth with the larger gravitational force , the sun or the moon .

A .   Calculation of force between earth and sun

Mass of earth (m1) = 5.972 * 1024 kg

Mass of sun (m2) = 1.989 * 1030 kg

Distance between the centre of sun and earth (r) = 149598000000 + 6371000 + 696342000 = 150300713000 m

Therefore , force =  (6.674×10−11)( 5.972 * 1024)( 1.989 * 1030)/( 150300713000)2

= 3.509 * 1022 N

Calculation of force between moon and earth

Mass of moon (m3) = 7.347 * 1022 kg

Distance between the centre of earth and moon (r) = 377739000 + 6371000 + 1738000 = 385848000 m

Therefore, force = (6.674×10−11)( 7.347 * 1022)( 5.972 * 1024)/(3858480002)

= 1.966 * 1020 N

Hence the force of attraction between sun and earth is more.

Q . 5 Using Newton’s Law of Universal Gravitation, explain why the sun’s gravitational attraction on the front and back of the Earth is almost the same but the moon’s gravitational attraction on the front and back of the

Earth is very different.

A.  We know that, using Newton’s laws of universal gravitation, that the force is inversely proportional to the square of distance between the objects . Also the distance between the centre of earth and sun is 150300713 km. Here adding or subtracting the radius of earth (6371 km) does make any appreciable change in the force value for the calculation of force at back and front. In case of the moon, the distance between the moon and earth is 385848 km. In this case, adding or subtracting the radius of earth in the distance do make appreciable changes in the force.

Q. 6. How does the moon create a bulge on the side of the Earth closest to it?

A.  The Moon does not orbit the center of the Earth. The Earth and the Moon orbit the common center of gravity which is closer to the Earth’s surface than to it’s center, on the side facing the Moon. As the Earth swings around that point, the side away from it is swung outward causing the bulge. Also, the side of the Earth farthest from the Moon gets less gravitational pull from it because of the increased distance. This is why a bulge in the side of earth occur.

Q .7. What causes a tidal bulge to form on the opposite side of the Earth from the moon?

A .  Water also bulges on the side opposite the moon. That is evidenced by the fact that high tides are about 12 hours apart not about 24. If you think of the Earth/Moon system as one system orbiting the sun, you will notice that even though the Earth is so much heavier the Moon is heavy enough that whole system wobbles around in its path, spinning about the center of gravity of the system. This leads to centrifugal forces on the water away from the center of the mass of the Earth/Moon system on the side away from the Moon and attraction to the Moon on the side toward the Moon.

Q . 8 How many high and low tides did Woods Hole, MA experience in the last lunar day? What type of tidal pattern did Woods Hole experience?

A .  For the time period of 10/12/13 (00.00 hrs) till 10/12/13(24.00hrs)

No. of high tides = 2

No. of low tides = 2

Type of tidal pattern is semi diurnal.

Q .  9   What are the tidal heights in Woods Hole, MA?

A .    Tidal heights are as follows

For Observed Values

Tidal height = (2.52-1.10) = 1.42 ft

Respective time of High tide is 02.06 hrs and low tide is 10.06 hrs

Next Tidal height = (3.12-0.82) = 2.3 ft

Respective time of high tide is 15.06hrs and low tide is 22.30 hrs .

For Predicted value

Tidal height = 1.78-0.23 = 1.55 ft

& = 2.32-(-0.05) = 2.37 ft

Q . 10. How do the observed and predicted data compare? What may have caused any differences between the observed and predicted data for Woods Hole, MA?

A .    From the data given we can say that the observed values are higher than the predicted values during the low and high tide .

The difference between the observed values and predicted values are of little significance at some and is considerable at some point. This difference occurs due to the change in air pressure and and change in temperature of air and water.

Q . 11 How many high and low tides did Mobile, AL experience in the last lunar day? What type of tidal pattern did Mobile experience?

A .   For the time period of 10/12/13 (00.00 hrs) till 10/12/13(24.00hrs)

No of high tide = 1

No of low tide = 1

It follows the wave pattern (sinusoidal curve) i.e diurnal .

Q . 12   What are the tidal heights in Mobile, AL?

Observed Value

Tidal height = (1.82-0.35) = 1.47 ft

Respective time of high tide is 03.00 hrs and low tide is 16.06 hrs .

Q . 13  How do the observed and predicted data compare? What may have caused any differences between the observed and predicted data for Mobile ?

A .   Here the observed and predicted value are very much in unison . Very small difference exist between them . Maximum difference between them is observed at 22.30 hrs CDT . The difference between the observed value and predicted value is due the wind speed  mainly.

Q . 14   How many high and low tides did Seattle, WA experience in the last lunar day? What type of tidal pattern did Mobile experience?

A .   No of high tide = 2

No of low tide = 2

Tidal pattern is mixed pattern .

Q . 15  What are the tidal heights in Seattle, WA?

A .   Observed value

Tidal heights = 10.76-(-0.13) = 10.89 ft

Respective time of high tide is 12.30 hrs and low tide is 05.00 hrs.

Tidal heights = 8.63-5.45 =3.18 ft

Respective time of high tide is 23.30 hrs and low tide is 18.42 hrs .

Predicted value

Tidal height = 10.76-(-0.01) = 10.77ft

Tidal height = 8.76-6.03 = 2.73 ft

Q .  16   How do the observed and predicted data compare? What may have caused any differences between the observed and predicted data for Seattle, WA?

A .  Here the observed values are smaller than predicted value . Also the difference is very small and is of the order 0.01 to 0.4 roughly .

The difference is caused basically due to change in wind speed , air temperature and air pressure .

Q . 17  Use the data provided for Wrightsville Beach and Wilmington, NC to complete Table I below.

A .                                    Table I. Tidal Height for Wrightsville Beach, NC (2009)

 Tidal Heights (ft) New Moon First Quarter Full Moon Second Quarter Jan 2.9 2.5 3.6 3.8 Feb 4.0 3.1 5.7 2.3 Mar 4.0 4.0 5.1 1.6 Apr 5.2 2.8 4.3 2.8 May 4.0 3.1 , 4.0 4.8 3.0 Jun 4.7 4.1 4.5 2.4 Jul 5.9 3.7 2.8 3.2 Aug 4.6 3.6 4.0 5.4 Sep 5.2 2.0 3.7 2.4 Oct 4.5 2.0 4.4 2.8 Nov 3.6 2.8 3.7 4.1 Dec 4.8 2.8 5.7 , 2.9 3.8

Q . 18   When the moon aligns with the sun we have either a new moon, moon between Earth and sun, or a full moon, moon is behind the Earth. At this special time, the tidal effects from both the sun and moon combine. Using Table I below, describe here if your data supports this idea.

A .   During new moon the tidal heights are like 5.9 , 5.2 , 4.9 , 4.8 ft etc . But the tidal height during full moon in the month of January is small (2.9ft). Also during full moon the tidal heights are like 5.7 , 4.5 ,4.8 ft etc. . But here also in the month of july tidal height is small(2.8 ft) .

So data’s given in table 1 satisfies the above concept well .

Q  . 19   During spring and fall equinox, the plane of the lunar orbit matches the plane of the Earth’s orbit around the sun. During these two times of the year, the pull from the sun and moon are aligned. Use the data in Table I below and describe the high and low tides around March 21 and Sept 21.

A .    During spring equinox , both moon and sun lies on the same side of earth and that too in the same straight line . Hence this causes a high tide. From the table it can be seen that the tidal heights are 4.0 ft , 5.2 ft etc

During fall equinox, moon lies on the opposite side of sun. So the side closest to moon experience high tide . Due to very less percentage change in the distance between the sun and the back of earth there is hardly any influence on it due to sun’s gravitation , where as the side of earth closest to sun due to high gravitational forces experience high tide . From the table it can be seen that tidal heights are like    5.2 ft 3.7 ft etc .

Q .  20    The Earth travels around the sun in an elliptical orbit. The Earth is closest to the sun in January when it is about 91 million miles away. In July it is furthest at almost 95 million miles away. Should being closer to the sun cause stronger tides? Explain. Does your data in Table I support this?

A .  No it does not cause considerable stronger tides . This is due to the fact the percentage change in the distance between them is very small therefore , very little effect on tides . From table 1 we can say that the tidal heights are 2.9 ft , 3.6 ft , 3.8 ft etc . in the month of January . Though the sun and earth are closest in January, it has no effect or very little effect on the tides .

Q . 21                                 Table II. Tidal Schedule for Wrightsville Beach, NC (2009)

 January Day Time of Moon Rise Time of Moon Set Time moon highest in sky 1st 10.18 hrs 22.09 hrs 16hr13min30sec 2nd 10.44 hrs 23.08 hrs 18hr24min20sec

Table III. Tidal Schedule for Wrightsville Beach, NC (2009)

 January Day Low Tide Time High Tide Time Low Tide Time High Tide Time Time moon highest in sky 1st 04.06am 10.20am 04.40pm 10.50pm 04.13pm 2nd 04.53am 11.00pm 05.26pm 11.37pm 06.24pm

Q . 22  When the moon is highest in the sky, or overhead, should you be in the tidal bulge? Explain.

A .  Yes , there will be tidal bulge . This is due to the fact that tidal bulge depends on the distance between moon and the Earth . Since , distance between the moon and the earth reduces in this case as a result tidal bilge occurs .

Q . 23   Does your data in Table III show a high tide when the moon is directly overhead? Explain your findings.

A .   No ,   This is because when the moon is directly overhead does not ensure it is close to the earth .

# Bible Books – Comparitive Religion

Book of Joshua

Book of Joshua is a narrative account of Israel as per the Christian Old Testament. Joshua, successor of Moses leads the twelve tribes of Israel to conquer Cannan following the orders of God to assign them their Promised Land. Rehab the harlot is important here as she helps Joshua’s spies to get information about Jericho and thus, is an important figure in Israelite history. Another event in the book was Israel army crossing Jordon River when Joshua dried it up to reach Jericho. As Joshua and army reached Jericho, they meet a mysterious man who claims to be a commander of God but does not give any instructions or messages. Israelites win the battles where they are obedient to God’s laws and orders and loose when they do not obey Him, like in Ai. Further, the book divides the conquered land amongst the twelve tribes as they settle in the conquered land. At the end, Joshua calls upon them to be faithful to God’s laws and to follow Him and their religion.

Book of Job

The Book of job falls under the wisdom genre of the Christian Old Testament. It addresses the basic question of human race that why does God give suffering to mankind. The book contains the story of Job, a blameless man who has complete faith in God. When Satan, “the adversary” challenges God that Job will curse God if He takes away all his blessings, i.e., children, flock, health, etc. Job doesn’t curse God through his trials, even when Satan inflicts him with skin boils. When he sits with his three friends, Eliphaz, Bildad, and Zophar, he curses the day he was born. The friends blame him that the misfortunes are due to his wrongdoing and God is punishing him for his deeds. Job says that he is being wrongly punished. Elihua, the fourth friend joins them telling Job must trust God and believe in his graciousness. At the end, God speaks to them rebuking the three friends, talks about omnipotent powers of God and tells them that they cannot understand his actions. God gives Job everything back.

Book of Ruth

The book of Ruth is a narrative account in the Old Testament. The main purpose of the book is unsure but it touches upon several ideas. The book begins with Elimelech, wife Naomi and two sons Mahlon and Chilion leaving Bethlehem to settle in Moab due to famine. When Elimelech dies, his two sons marry Moabite women, Ruth and Orpah. Thus, the book accepts the practise of intercaste marriage. After the sons die, Naomi urges their wives to return to their home but Ruth refuses to leave her highlighting faithfulness. Ruth goes to work in the fields of Boaz, a distant relative of Elimelech. Naomi wants Ruth to marry Boaz to continue family name through Levirate law of marrying within the family.  Boaz also agrees to ‘redeem’ Ruth, showing the theme of kindness. After the marriage is sanctioned by Ploni Almoni and other town members, they marry giving birth to Obed who is the grandfather of David, the greatest king of Israelites and an ancestor of Jesus. Thus, the book outlines the family history of Jesus.

Book of Ezra

The book of Ezra is an important narrative of the Old Testament. The central purpose of the book is to bring in the theme of Restoration of the Jews and the community. After the Babylonian captivity, God of Israel inspired a Persian king, to commission the restoration of Jerusalem. The three missions assigned to the three leaders are rebuilding the Temple assigned to Zerubbabel through the return of the exiles during Cyrus I, purifying the Jewish community assigned to Ezra and building a wall around the city assigned to Nehemiah, the last two during the reign of Artaxerxes I. The third mission is given in the next book of Nehemiah. Here, the return of exiles is given along with Ezra going to Israel and laying down the laws which he did by reading the Law of Moses which the Lord prescribed for Israel. The law tells the people to not marry with the non – Jews. Haggai, the main prophet during the times of Ezra assisted him in carrying out the second mission.

Book of 1 Samuel

The primary theme of the book of 1 Samuel, a narrative, is the transition of Israel from a theological state to a monarchy to a political estate. Samuel is born to Hannah whom she gives up to Eli, the chief priest of Shiloh where the Ark of Covenant is located. God chooses Samuel to carry out His sermons. In a battle, Philistines capture the Ark and take it with them. But, when the Philistine people start dying due to diseases, they return the Ark to Israel. As Samuel grows old, Israelites demand a king. Samuel and God claim that if the people are faithful to God, monarchy will not be doomed. God chooses Saul as the king. Despite many victories, Saul commits mistake by not giving proper recognition to priest in performing ritual sacrifices and favouring physical rituals over theological orders. God decides to bless David, a shepherd and youngest son of Jesse as the new king. He defeats Philistines in a battle with Goliath, the nine feet giant through divine powers of God. After Saul, David becomes the ideal king of Israel for a long time.

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# Probability Solution

Solution 2:

Possessions value- \$50000

Probability of accident=.1

This means that the expected value of loss is =10 % of 50000=\$5000

1. If the insurance fee(f) is \$5500, he will not go for the insurance, since the cost of insurance is higher than the expected value of loss
2. U=x ^.4

By the utility function , we can get the utility by applying the value

Merchant expected utility if un-insured is

(.9)*( 50000)^.4

To get that utlity with certainty , he would need the following risk free wealth

U(x)= x^.4

U(x)=  .9 * (50000)^.4

X= (.9)^.4 *50000

X=47936.58

So he will be willing to pay (1-.9^.4)*50000=2063.424\$

Profit- 500000, prob=.9

Loss= 2500000, prob=.1

In linear case , expected point= 500000*.9-2500000*.1=200000

Hence it will go ahead with the project

U(x)=2x-.1×2+100

Current assets=3 million

In the first case, asset become, 3+.5=3.5, in the second case asset becomes, 3-2.5=.5,

The expected utility if uninsured is

=.9*(-.1*(3.5)^2 +2(3.5) +100)+.1*(-.1*(.5)^2+2(.5)+100)

=117.4

We need the asset level that corresponds to this value

2x-.1x^2+100=117.4

X is imaginary!

The utility function is unique because it is a quadratic equation, which may have imaginary roots

4

b.

Let the probability of success be p, and failure 1-p

Successà Asset=4mn

Failureà Asset=.5mn

U(x)=x^.5

Utility outcome= p(4)^.5+(1-p)(.5)^.5

U(x)=x-.1x^2

Utility outcome=p(4-.1(4)^2) + (1-p)(.5-.1(.5)^2)

U(x)=1-e^-x

Utility outcome=p (1-e^-4) +(1-p)(1-e^-.5)

U(x)= p(1-(3/4)^4)+(1-p)(1-(3/4)^.5)

# Apportionment

 Apportionment State Population % Representation Hamilton numbers Integer Part Fractional Part Assign Additional manually Seats after apportionment 1 15475 0.02907807 2.91 2 0.91 2nd priority 3 2 35644 0.066976332 6.70 6 0.70 5th priority 7 3 98756 0.185566003 18.56 18 0.56 18 4 88346 0.166005246 16.60 16 0.60 16 5 369 0.000693364 0.07 0 0.07 1st priority 1 6 85663 0.160963795 16.10 16 0.10 16 7 43427 0.081600863 8.16 8 0.16 8 8 84311 0.158423339 15.84 15 0.84 3rd priority 16 9 54730 0.102839598 10.28 10 0.28 10 10 25467 0.04785339 4.79 4 0.79 4th priority 5 Total 532188 1 100.01 95 5.01 100 We first calculate the perventage representation of each state in the total population of the country. Then we find the Hamilton’s number by converting them to percentages, till 2 decimal places. Then we separate the integer and fractional parts. The integer seats are adding upto 95, hence 5 seats have to be alloted The fractional parts determine the priority that the states will get for remaining seats. The higher fractions will get priority. However, the state 5 has 0 integer part, suggesting that no representative shall be selected from there, which is not allowed, hence we assign first priority to state 5, and then based on fractional part. The absolute unfairness betwwe state 1 and state 2 is the difference of their average constituency 394 The relative unfairness 0.077463559

# Interval Notation

1.  Solve and express your solution set in interval notation.

|(2x-1)/(3)|>=(5)/(6)

Remove the absolute value term.  This creates a \ on the right-hand side of the equation because |x|=\x.

(2x-1)/(3)>=\((5)/(6))

Set up the + portion of the \ solution.

(2x-1)/(3)>=(5)/(6)

Solve the first equation for x.

x>=(7)/(4)

Set up the – portion of the \ solution.  When solving the – portion of an inequality, flip the direction of the inequality sign.

(2x-1)/(3)<=-((5)/(6))

Multiply each term in the inequality by 3.

2x-1<=-3((5)/(6))

Multiply -3 by each term inside the parentheses.

2x-1<=-(5)/(2)

Move all terms not containing x to the right-hand side of the inequality.

2x<=-(3)/(2)

Divide each term in the inequality by 2.

x<=-(3)/(4)

The solution to the inequality includes both the positive and negative versions of the absolute value.

x>=(7)/(4) or x<=-(3)/(4)

3.   Under certain conditions, the power P, in watts per hour generated is by a

windmill with winds blowing v miles per hour is given by

=  .

How fast must the wind blow in order to generate 120 watts of power in 1 hr?

the power P, in watts per hour, generated by a windmill with winds blowing v miles per hour is given by
P(v)= 0.015v^3

120 = 0.015v^3
120/0.015 = v^3
v = 20 mph

6.    Sketch the graph of the function,

7.   Find a rational function that satisfies the given conditions.

Vertical asymptotes x  =  -3  and x  =  5;      x-intercept  (-1, 0)

Vertical asymptotes x  =  -3  and x  =  5

Means

The   denominator will be = (x+3)(x+5)

X intercept = (1,0)  so (x-1)

Equation = a*(x-1)/( x+3)(x+5)

8.  The frame of a picture is 28 cm by 32 cm outside and is of uniform width. What

is the width of the frame if 192  of the picture shows?

The shape of the picture is a rectangle formed by removing a constant from both

Dimensions of the outer frame is  28 x 32.

(28 – c)(32 – c) = 192
896 – 60c + c^2 = 192
c^2 – 60c + 704 = 0

C= 16 , 44

So  the dimensions are 12,16.

C is twice the frame so width of frame= 16/2 = 8 cm

9.    Solve the inequality and write the solution set in interval notation.

|(x+3)/(x-4)|<2

Remove the absolute value term.  This creates a \ on the right-hand side of the equation because |x|=\x.

(x+3)/(x-4)<\(2)

Set up the + portion of the \ solution.

(x+3)/(x-4)<2

Solve the first equation for x.

x<4 or x>11

Set up the – portion of the \ solution.  When solving the – portion of an inequality, flip the direction of the inequality sign.

(x+3)/(x-4)>-(2)

To set the left-hand side of the inequality equal to 0, move all the expressions to the left-hand side.

(x+3)/(x-4)+(2)>0

Remove the parentheses around the expression 2.

(x+3)/(x-4)+2>0

Multiply each term by a factor of 1 that will equate all the denominators.  In this case, all terms need a denominator of (x-4).

(x+3)/(x-4)+2*(x-4)/(x-4)>0

Multiply the expression by a factor of 1 to create the least common denominator (LCD) of (x-4).

(x+3)/(x-4)+(2(x-4))/(x-4)>0

The numerators of expressions that have equal denominators can be combined.  In this case, ((x+3))/((x-4)) and ((2(x-4)))/((x-4)) have the same denominator of (x-4), so the numerators can be combined.

((x+3)+(2(x-4)))/(x-4)>0

Combine all similar expressions in the polynomial.

(3x-5)/(x-4)>0

Since this is a ‘greater than 0’ inequality, all intervals that make the expression positive are part of the solution.

x<(5)/(3) or x>4

The solution to the inequality includes both the positive and negative versions of the absolute value.

x<4 or x<(5)/(3)

10.

The function,   , gives the height s, in feet, of an

object thrown from a cliff that is 1920 ft high. Here t is the time, in seconds,

that the object is in the air. For what times is the height less than 640ft?

for time  is the height less than 640 we have to equate

-16*t^2+32*t+1920 < 640

-16*t^2+32*t+1280 < 0

-t^2-2*t+80 < 0

(t-1)^2 > 81

t-1 > 9

t > 10

For times more than 10 sec.

# INCOME OF BROWNS FAMILY

 INCOME OF BROWNS FAMILY Family member Salary Overtime Bonus Total Earning Mr Brown 34403.2 8270 2000 44673.2 Salary Hourly Work income Commision of Sales Total Earning Mrs Browns earning 26000 3900 2500 32400 Joe- Teenaged Son Part time income 6760 6760 Other Income Interest Income ( Mrs Brown) 390 ( Assuming the money is put into account this year) Total Family Annual Income 84223.2 Tax of Mr Brown 11168.3 ( Tax on Mr Brown Salary calculated) Tax of Mrs Brown 8100 Total Disposal Income for family 53904.9 Total disposable income EXPENSES OF BROWNS FAMILY Fixed Expenses Column1 Weekly Monthly(\$) Annually(\$) Mortgage payment 992 11904 Maintenance for Home 200 2400 Medical Insurance 150 1800 Co-payment of health check ups 35 280 (Assuming half yearly visit by 4 family members) Mr Browns prescription co-payment 15 180 Sandy’s pocket money 10 520 Total 17084 36820.9 Variable Groceries + Meals 150 600 7800 Entertainment 200 2400 Family Trip 400 Credit Card 75 900 ( assuming minimum amount paid of 75\$, this is variable expense) Bills + fines 100 1200 Clothings 1000 Service ( cleaning, repairs) 200 Transportation 60 3120 Total 17020 Total Expense ( Fixed+Variable) 34104 Savings for Retirement (5%) 4950.225 Net Income (after fixed expense, variable expense and savings for retirement) 14850.68 Credit Card It will take 110 months to pay off the card dues, by paying 75\$ a month. The calculator used is here http://www.bankrate.com/calculators/credit-cards/credit-card-payoff-calculator.aspx If we have to pay off the credit card due in 5 years, we must pay \$111.22 per month. The calculator is http://www.bankrate.com/free-content/credit-cards/calculators/free-credit-card-payoff-calculator/ Column1 Column2 Column3 Column4 Joe’s Budget Income 6760 Expenditure Monthly Quarterly Education 10 20 Tuition 100 1200 Entertainment 100 1200 Clothing 250 Transportation 150 1800 Others 200 Total 4670 Savings 2090

# Inventory Management System

Inventory management system

# Abstract

Here as per the case study Margaret uses manually managed system for every bits and pieces of her store and cafeteria which causes hazards and wastage of paper, man power. Inventory management system is a vast task divided into groups of tasks called storing data, retrieving data, putting data in order etc. here we will try to explain how a management information system for automating inventory management, invoice generation, receiving processes, requiring customer order fulfillment, and having Web-based self-services would help her business to compete with major book retailers. Also we will Explain how through the use management information systems, her competitors are lowering costs and improving profit margins through increasing efficiency.

# Inventory management system

Management information system is the machine controlled system of storing various data and putting  them in order to be called information or meaningful data.  Management information study can be used for automating inventory management. To keep record of an inventory we have to categorize the source of income. The amount of money, the period over when the revenue got collected etc. these helps us to get the larger picture and helps us to further build the function and extend it.

how a management information system for automating inventory management To create management information system for automating inventory management we need to install a few machines like bar code reader, bar code strips, computer for calculation and a software system for the specific product.

Basically, the organizations work like this. First, bar codes or RFIDs communicate scanners which items customers are buying. The scanners convey the information to computers by reading the bar codes and transporting that information to the software. The software then construes the numbers from the bar code and matches those numbers to the type of product they represent. This permits the wholesaler to track sales and inventory — either at the checkout counter or with a hand-held scanner — keeping the store well-informed of which items are selling.

Particular software keeps track of how much stock is going out the door via consumptions and how much leftovers on shelves and in the storeroom, giving directors a real-time image of what’s happening. The software also examines the data and makes references for re-ordering plans. Sometimes, they’re automated to mechanically order at a assured point. It’s significant to note, though, that good systems consent room for human decision-making. The systems provide good information to support choices but leave the final call up to managers.

Maximum retailers, nonetheless, have bought into the vast compensations presented by such systems. They comprise the high competence, the need for less warehouse space, less cash tied up in accounts and better sales. The organizations also endorse better information sharing amid the retailer and the vendor, which helps drive down cost for both, as well as for the consumer.

The welfares of contemporary account management systems aren’t just for the trade and trade sectors. They also offer great recompenses for any group that achieves a supply chain for expendable items, such as the military and medical facilities.

invoice generation

invoice generation includes the application made for particular business, for example in a book store the inventory management system should get its sku number, customers mobile number, address, product’s id number, quantity of product, date and time and branch of shop, name of the sales person, a clear name of customer along with his/her signature. The description of the product.

Web based marketing

Online store publication of the shop makes people go to the site and people takes interest as no body these days have enough time to go to a shop and gets the product. We have to choose an unique design, customer friendly registration and login process so that the steps are small and easy to understand. The admin should get payment method installed in the site so that customers can pay for what they are buying. The payment procedure should be secure enough so that customers can trust the site management.

# References

1. Laudon, Kenneth C.; Laudon, Jane P. (2009). Management Information Systems: Managing the Digital Firm (11 ed.). Prentice Hall/CourseSmart. p. 164.
2. Transaction processing systems (TPS) collect and record the routine transactions of an organization. Examples of such systems are sales order entry, hotel reservations, payroll, employee record keeping, and shipping.
3. Bidgoli, Hossein, (2004). The Internet Encyclopedia,
4. ^ Chambers Dictionary, 1998, Chambers Harrap, Edinburgh, p. 845
5. Financial dictionary, formerly at http://www.specialinvestor.com/terms/1072.html, Special Investor
6. aspenONE Supply & Distribution for Refining & Marketing
7. Relevance Lost, Johnson and Kaplan, Harvard Business School Press, 1987, p126
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